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0=-16x^2+98x+147
We move all terms to the left:
0-(-16x^2+98x+147)=0
We add all the numbers together, and all the variables
-(-16x^2+98x+147)=0
We get rid of parentheses
16x^2-98x-147=0
a = 16; b = -98; c = -147;
Δ = b2-4ac
Δ = -982-4·16·(-147)
Δ = 19012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19012}=\sqrt{196*97}=\sqrt{196}*\sqrt{97}=14\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14\sqrt{97}}{2*16}=\frac{98-14\sqrt{97}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14\sqrt{97}}{2*16}=\frac{98+14\sqrt{97}}{32} $
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